Math, asked by ram18170, 1 year ago

a woman is thrice as old as his son .five years ago the woman was four times as old his son .find their presents age

Answers

Answered by BlackVenom05
0

Solution -

Let the present age of son be x yrs

So, the present age of woman be 3x yrs

Son's age 5 years ago = (x - 5) yrs

Woman's age 5 years ago = (3x - 5) yrs

According to Question,

(3x - 5) = 4(x - 5)

⇒ 3x - 5 = 4x - 20

⇒ 3x - 4x = - 20 + 5

 [ ∵ By transposition ]

⇒ - x = - 15

⇒ x = 15

Required Ages -

Son's age = x = 15 yrs

Woman's age = 3x = 3(15) = 45 yrs

∴ The present age of son is 15 years and the present age of woman is 45 years

#Be Brainly

Answered by Anonymous
0

Let the age of son be x

Let his father's age be 3x

Five years ago, age of son = x - 5

Five years ago, age of father = 3x - 5

5 years ago the man was four times as old as his son = 4(x - 5)

According to the question,

3x - 5 = 4(x - 5)

3x - 5 = 4x - 20

3x - 4x = -20 + 5

x = 15

x = 15

Present age of son is x

=> 15 years

Present age of father =. 3x

=> 3 * 15

=> 45 years

∴ The age of son and his father is 15 years and 45 years respectively.

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