Question

a woman's son is two years older than her daughter age is three times the sum of the age of her children after 5 years she will be 47 years old find the present ages of the children

Answer 1

let daughter's age be x and son's age be y then
y=2+x
x-y=2. (1)
after five years
5+3(x+y)=47
3x+3y=42
x+y=14
by elimination,
x=6 and y=8

Answer 2

Solution:-

• The present age of the woman is

47 - 5 = 42.

• Since the woman's age is 3 times the sum of the ages of the children,

• This sum is 42/3 = 14.

• So for children ages you have two equations:

=> s + d = 14,

=> s - d = 2.

• Every time when you see two equations like these, add them.

• You will get

=> 2s = 14 + 2,

=> 2s = 16,

=> s = 16/2 = 8.

Thus son is 8 years now.

The daughter is 8 - 2 = 6 years.

i hope it helps you.