verify p(x)=x^2-4x+5 doesn't have zeros of polynomial
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Use discriminant here..
D=0 means two equal and real zeroes.
D>0 real and distinct zeroes
D<0 no real zeroes
Here in this case
D=(-4)^2-(4)(5)
D=16-20
since D<0 hence it has no real roots
D=0 means two equal and real zeroes.
D>0 real and distinct zeroes
D<0 no real zeroes
Here in this case
D=(-4)^2-(4)(5)
D=16-20
since D<0 hence it has no real roots
Ironspidey:
i mean my question
It's better to ask your teacher. because I m unable to solve it since you don't know basics.
ok thanks
can u say me basics
p(x)=x^2-4x+5.
let p(x)=0
x^2-4x+5=0
x^2+x-5x+5=0
x(x+1)-5(x-1)=0
so,there are no zeros for p(x)
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