a women has Rs 10,000 with her. she calculated that she could spend Rs x everyday on her holiday. she spent Rs (x–50) everyday and extended holiday for 10 days. find x
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Hi ,
Amount Tourist has = Rs 10000
If he spend Rs x each day
Let the number of days he spent
Rs 10000 = y
Now ,
xy = 10000 -------( 1 )
If he spends Rs ( x - 50 ) , the numberof days he spends the same
amount = ( y + 10 )
( x - 50 ) ( y + 10 ) = 10000
xy + 10x - 50y - 500 = 10000
10000 + 10x - 50y - 500 = 10000
10x - 50y - 500 = 0
Divide each term with 10 we get
x - 5y - 50 =0
x = 5y + 50 ----( 2 )
Put x value in ( 1 )
( 5y + 50 ) y = 10000
5 y^2 + 50y = 10000
Divide each term with 5
y^2 + 10y - 2000 = 0
y^2 - 40y +50y -2000 =0
y ( y - 40 ) + 50 ( y - 40 ) = 0
( y - 40 ) ( y + 50 ) = 0
y - 40 = 0 or y + 50 = 0
y = 40 or y = -50
y should not be negative
y = 40
Put y value in ( 1 )
x × 40 = 10000
x = 10000/ 40
x = 1000/4
x = 250
Hope This helps :)
Amount Tourist has = Rs 10000
If he spend Rs x each day
Let the number of days he spent
Rs 10000 = y
Now ,
xy = 10000 -------( 1 )
If he spends Rs ( x - 50 ) , the numberof days he spends the same
amount = ( y + 10 )
( x - 50 ) ( y + 10 ) = 10000
xy + 10x - 50y - 500 = 10000
10000 + 10x - 50y - 500 = 10000
10x - 50y - 500 = 0
Divide each term with 10 we get
x - 5y - 50 =0
x = 5y + 50 ----( 2 )
Put x value in ( 1 )
( 5y + 50 ) y = 10000
5 y^2 + 50y = 10000
Divide each term with 5
y^2 + 10y - 2000 = 0
y^2 - 40y +50y -2000 =0
y ( y - 40 ) + 50 ( y - 40 ) = 0
( y - 40 ) ( y + 50 ) = 0
y - 40 = 0 or y + 50 = 0
y = 40 or y = -50
y should not be negative
y = 40
Put y value in ( 1 )
x × 40 = 10000
x = 10000/ 40
x = 1000/4
x = 250
Hope This helps :)
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