Question

A women heterozygous of B blood group married a man of AB blood group. their probability of having child of the A blood group is
1- 25%
2-50%
3-75%
4-100%

Answer 1

Answer:

your ans is 1)25℅

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Explanation:

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Answer 2

Answer:

The probability of having a child of the A blood group is 25% and the correct option is 1-

Explanation:

ABO blood group is controlled by single gene. It has three allelic forms and the allelic forms are $I^{A}$ and $I^{B}$  which are dominant over $i$. $I^{A}$ and $I^{B}$ produce surface antigen A and surface antigen B respectively, whereas $i$ does not produce any antigen.

So, we can say-

• The blood type A will have $I^{A} I^{A}$ or$I^{A}$$i$ types of genotypes.
• Blood type B will have $I^{B} I^{B}$ and $I^{B} i$ types of genotypes.
• Blood type AB will have $I^{A} I^{B}$ type of genotype.
• Blood type O will have '$i$$i$' genotype.

In the question it is said that a women is heterozygous for B blood, it means that the genotype will be $I^{B}i$ and this woman married a man, who has a blood group of AB.

So, we can say that the probability of having child of A blood group is 25%. The correct option is 1-