Question

a women reduces her weight in the ratio 7:5.what does her weight become when originally was 91kg?

Answer 1

Ratio= 7:5.
Original weight= 91 kg.

Let her present weight (weight after reducing) be x

7/5= 91/x

On cross multiplying,

7x= 91×5

7x= 455

x= 455/7

x= 65.

Therefore her present weight is 65 kg.

Answer 2

let her new weight be X
7 : 5 = 91 : X
$\frac{7}{5} = \frac{91}{x} \\ 7x = 91 \times 5 \\ x = \frac{91 \times 5}{7} \\ x = 13 \times 5 \\ x = 65$
thus, the answer is 65kg.....
hope it helps you....