Question

a women's son is 2 years older than her daughter her age 3times of her children after 5 yrs she will be of 47 yrs find the present age

Answer 1

let x is son age (present) y = daughter age (present) 

given x = 2+y  ; and given 3(x) + 5 = 47 (this is not present age of women)

3(2+y) + 5 = 47  ==> 3y = 36  = y = 12 (this age is five years from now )

So y age present is 12-5 = 7 ; x=2+y ==> 7+2 = 9 is the age of x

there fore present age of son 9 ,daughter 7

Answer 2

Solution:-

• The present age of the woman is 47 - 5 = 42.

• Since the woman's age is 3 times the sum of the ages of the children,

• This sum is 42/3 = 14.

• So for children ages you have two equations:

=> s + d = 14,

=> s - d = 2.

• Every time when you see two equations like these, add them.

• You will get

=> 2s = 14 + 2,

=> 2s = 16,

=> s = 16/2 = 8.

Thus son is 8 years now.

The daughter is 8 - 2 = 6 years.

i hope it helps you.