Question

A women's son is 2 years older than her daughter. Her age is three times the sum of the ages of her children after 5 years she will be 47 years old. Find the present age of children.

Answer 1

daughter s age = x
sons age = x + 2

mothers age after five years =
3[(x +5 )+( x +2 +5)]
47 = 3(2x +12)
47 = 6x + 36
47 - 36 = 6x + 36-36
11 = 6 x
11/6 = x

so daughters age =[ (11*12 )/6] 12
=22 / 12
= 1 10/12 years
sons age = x +2
= 1 10/12 + 2
=3 10/12 years


hope it helps

Answer 2

Solution:-

• The present age of the woman is 47 - 5 = 42.

• Since the woman's age is 3 times the sum of the ages of the children,

• This sum is 42/3 = 14.

• So for children ages you have two equations:

=> s + d = 14,

=> s - d = 2.

• Every time when you see two equations like these, add them.

• You will get

=> 2s = 14 + 2,

=> 2s = 16,

=> s = 16/2 = 8.

Thus son is 8 years now.

The daughter is 8 - 2 = 6 years.

i hope it helps you.