a Women throws an object mass 500 gm with speed of 25m/sec what is the impale imparted to the object
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Mass of the object (m) = 500g = 0.5 kg
Speed of the object (v) = 25 m/s
(i) Impulse imparted to the object = Change in the momentum = mv-mu
= m(v-u)
= 0.5(25-0) = 12.5 N-s
(ii) Velocity of the object after rebounding = -25/2 m/s
v’ = -12.5 m/s
Change in momentum = m(v’ - v)
= 0.5 (-12.5 -25)
= -18.75 N-s
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