Question

A wood block of mass 3kg is resting on the surface of a rough incline surface. Angle of inclination of the surface

is as shown in fig.

(i) Name the forces 1,2 and 3

(ii) If the coefficient of static friction is 0.2. Calculate the value of all the three forces (Take g = 10m/s2
)


Plz give me correct answer according to 11th class​

Answer 1

Answer:

fr = mu N

3 root 3

Explanation:

(a) 1 is weight of body

    2 is force of friction  

    3 is normal reaction

(b) if cofficient of friction is 0.2

   1 . weight = 3*10= 30N

​    2.NORMAL reaction =mg cos0 3*10*31/2/2=25.98 N

   3. force of friction = normal reaction * 0.2 = 5.20 N

so, block will start moving