Question

A wooden article was made by scooping out a hemisphere from one end of the cylinder and a cone from other end. If the height of the cylinder is 40 cm, radius of the cylinder is 7cm and height of the cone is 24cm, then find the volume and TSA of the article

Answer 1

Lateral height of cone = $\sqrt{7^2 + 24^2 } =25cm$

Surface Area of Article = CSA of Cylinder + CSA of Cone + CSA of Cone

= $2\pi (7)(40)+ \pi (7)(25) + 2 \pi (7)^2$

=2618 sq cm

Volume of article = Volume of cylinder - [Volume of cone + volume of hemisphere]

= $\pi (7)^2 (40) - [ (1/3) \pi (7)^2 (24) + (2/3) \pi (7)^3 ]$

= 12628/3 cubic cm

Answer 2

Answer:

Lateral height of cone =

Surface Area of Article = CSA of Cylinder + CSA of Cone + CSA of Cone

=

=2618 sq cm

Volume of article = Volume of cylinder - [Volume of cone + volume of hemisphere]

=

= 12628/3 cubic cm