Physics, asked by Moksh28332, 20 days ago

A Wooden block of dimensions 100 × 80 × 50 is placed on a table top . Find the pressure exerted by the block on the table . Taking density of block as = 4kg/m^3 and g = 10m/s^2 ?



Please answer urgent . Help me pls !​

Answers

Answered by pavansaichimma
0

Answer:

Explanation:

Mass of the wooden block, m=5kg

Thrust due to wooden block,

Mg=5kg×9.8ms  

−2

=49N

(a) Surface area of 20cm×10cm surface,

A=(20×10)cm  

2

 

=(0.2×0.1)m  

2

 

=0.02m  

2

 

P=  

A

mg

 

P=  

0.02m  

2

 

49N

=  

0.02

49

Nm  

−2

 

or Pressure, P=2450Nm  

−2

.

(b) Surface area of 40cm×20cm surface,

A=(40×20)cm  

2

 

=(0.4×0.2)m  

2

=0.08m  

2

 

P=  

0.08m  

2

 

49N

=  

0.08

49

Nm  

−2

 

or Pressure, P=612.5Nm  

−2

.

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