Question

a wooden block of mass 0.010 kg is dropped from the top of a cliff 100 m high. simultaneously A bullet of mass 0.010 kg is fired from the foot of a cliff upward with a velocity of 100 m per second. the bullet and the wooden block will meet each other after the time in seconds is?

Answer 1

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good afternoon___________✌️✌️✌️✌️✌️




Let they meet after t second

If block travels 's'm distance then in same time the bullet travells(100-s)m

For block

s=0×t+12s=0×t+12×10×t2×10×t2

For bullet

100−s=100×t+12100−s=100×t+12(−10)×t2(−10)×t2

Solving this;

we get t=1second