Question

A wooden block of mass 6 kg is pulled across a rough surface by a 54 N force against a friction force F. The acceleration of the block is 6m/s^2 then value of the friction force F is....?

Answer 1

Force1

=mass×acceleration

=6×6N

=36N

Given applied force=54N

Then frictional force= 54-36N

=18N

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Answer 2

Given,. friction=F

m=6kg

force=54Newton

acceleration=6m/s^2

As friction gives retardation to the force,so total acceleration

=(6m/s^2+F)

force =m❌(a+F)

54 = 6❌(6+F)

6+F= 54/6

= 9

retardation=9-6 m/s^2

=3m/s^2.

So ,retardation= 3m/s^2.

F1= m❌a

=6❌6

=36 netwon

But,force =54 N

So, frictional force=54-36

=18 N.