A wooden block of volume 1000cm2 is suspended from a spring balance. Its weight is 12 n in air. It is suspended in water such that half of the block is below the surface of water. The reading of spring balance is-
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A wooden block of volume 1000cm3is suspended from a spring balance. It weighs 12 N in air. It is suspended in water such that half of the block is below the surface of the water. The reading of the spring balance is ..
Volume of the wooden block=1000cm3 =0.001 m3
Weight=Mg=12N
When half the ball is in water (density of water is 1 kg/m3), it experiences an upthrust due to half weight submerged apart from the weight force.
Immersed volume=500cm3 =0.0005 m3
Upthrust=mass of the water displaced X g= (density of water) X (volume) X (g)
=(1) X (0.0005) X (10)=0.005 N
Net force on the block now is: downward weight - upthrust=12-0.005=11.995N
Volume of the wooden block=1000cm3 =0.001 m3
Weight=Mg=12N
When half the ball is in water (density of water is 1 kg/m3), it experiences an upthrust due to half weight submerged apart from the weight force.
Immersed volume=500cm3 =0.0005 m3
Upthrust=mass of the water displaced X g= (density of water) X (volume) X (g)
=(1) X (0.0005) X (10)=0.005 N
Net force on the block now is: downward weight - upthrust=12-0.005=11.995N
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