Question

A wooden block of weight 60 N is placed on a table. The force exerted by the surface of the table on the block will be​

Answer 1

Explanation:

R.E.F image

The FBD for the box of mass m when put on the table is,

The normal force N

1

is equal to the weight of the box.

N

1

=mg

The FBD of the first box when an identical box of mass m is placed above it is,

The normal force N

2

is equal to the weight of the second box.

N

2

=mg

The normal force N

3

is equal to the combined weight of the boxes.

N

3

=2mg

Clearly, N

1

=N

2

<N

3

Hence, option C is correct.

Answer 2

Explanation:

60×9.8=588newton

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