A wooden object floats in water kept in a beaker. The object is near a side of the beaker. Let P1, P2, P3 be the pressures at the three points A, B and C of bottom as shown in the figure.
Figure
(a) P1 = P2 = P3
(b) P1 < P2 < P3
(c) P1 > P2 > P3
(d) P2 = P3 ≠ P1
Answers
Answered by
1
Answer:
P1=P2=P3
Explanation:
As we know that liquids exert equal force in all directions. So force exerted on all points on bottom will also be equal.
Similar questions