Question

A wooden slab starting from rest ,slides down a iclined plane of length 10m with an acceleration of 5m/s2 what would be its speed ast the bottom of the inclined plane

Answer 1

Since object starts from rest initial speed u=0
Final speed v is required to be calculated.
Acceleration a is given to be 5m/s2
Distance s is 10 m/s
Using v2-u2=2as
V2=2*10*5
V2=100
V=10m/s