a wooden slab starting from rest slides down an inclined plane of length 10m with an acceleration of 5m/s.. what would be its speed at the bottom of the inclined plane?
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Wooden slab starts sliding down from rest
So the initial velocity u=0
The length of the inclined plane is 10 m
So s=10
Its acceleration is 5m/s²
So a=5m/s²
We need to find the final velocity i.e v
Using the equations of motion
v²-u²=2as
v²-0²=2*5*10
v²=100
v=√100
So v is 10
The final velocity of the Wooden slab is 10m/s
So the initial velocity u=0
The length of the inclined plane is 10 m
So s=10
Its acceleration is 5m/s²
So a=5m/s²
We need to find the final velocity i.e v
Using the equations of motion
v²-u²=2as
v²-0²=2*5*10
v²=100
v=√100
So v is 10
The final velocity of the Wooden slab is 10m/s
keerthi03:
great pa thanks a lot
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