A wooden wheel of radius r is made up of two semicircular parts two parts are held together by a ring made of a metal
Answers
Answered by
1
If temperature increases by ∆T,
Increase in length L, ΔL=LαΔT
⇒ΔLL=αΔT
Let tension developed in the ring is T,
$\frac{T}{S} = Y\frac{{\Delta L}}{L} = Y\alpha \Delta T\$
⇒T=SYαΔT
From FBD of one part of the wheel,
F=2T
Where, F is the force that one part of the wheel applies on the other part.
F=2SYαΔT
Increase in length L, ΔL=LαΔT
⇒ΔLL=αΔT
Let tension developed in the ring is T,
$\frac{T}{S} = Y\frac{{\Delta L}}{L} = Y\alpha \Delta T\$
⇒T=SYαΔT
From FBD of one part of the wheel,
F=2T
Where, F is the force that one part of the wheel applies on the other part.
F=2SYαΔT
Attachments:
Similar questions