Question

A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?
A) 13/42 B) 17/42 C) 5/42 D) 3/14

Answer 1

Explanation:
3 letters can be choosen out of 9 letters in 9C3
ways.

More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in (4C2*5C1)+4C3
ways

Hence,required probability = (4C2*5C1)+4C39C3
4
C
2
*
5
C
1
+
4
C
3
9
C
3
= 17/42

Answer: B) 17/4