Question

a work of 12.5 is done in moving a charge of + 25 coulomb from infinity to point A the potential at Ais


please answer fastly​

Answer 1

Answer:

Given:

Work done = 12.5 J

Charge transported = 25 C

Charge transported from infinity to point "A".

To find:

Potential at point "A"

Concept:

Potential difference is the work done to transport a unit positive charge from one point to another.

We assume that potential at infinity is zero.

Formulas used:

∆V = (Work)/(Charge)

Calculation:

∆V = (Work)/(Charge)

=> 0 - VA = (12.5)/(25)

=> VA = - 0.5 volts

So Potential at point A is

(- 0.5) volts.

Answer 2

Question :-----

• Potential at Point A ..

Given :-----

• work done = 12.5 J
• Charge Transported from infinity to Point A = 25C

Formula used :------

• A potential difference of one Volt is equal to one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit.
• If potential difference is taken as V, work done W and the charge moved as Q then the relationship is :V = W/Q
• The S.I unit of potential difference is volt.
• Assume Potential at infinity = 0

Solution :----

Putting values we get,

0 - V = 12.5/25

0 - V = 125/250

0 - V = 1/2

0 - V = 0.5

V = (-0.5) Volts ..

So, Potential At point A is (0.5 volts)