Question

A work of 146 kj is a performed in a order complex 1 kilo mole of a gas evidently and in this process the temperature of a gas increases by a7 celsius what is the atomicity of a gas is equal to 8.3 mole per mole

Answer 1

Answer:

diatomic gas

Explanation:

n=103,ΔW=−146×103J,ΔT=T2−T1=7∘C

 ΔW =

ΔW=nR(T1−T2)/γ−1=−nR(T2−T1)/γ−1

−146×103=−103×8.3×7/γ−1

γ−1=0.4

γ=1.4, diatomic gas

as we know  γ of diatomic gas = 7/5 =1.4