Question

A worker needs to pack 350 kg of rice and 150 kg of wheat in bags such that each bag weighs the same. Each bag should either contain rice or wheat. Which option shows the correct steps to find the greatest amount of rice/wheat the worker can pack in each bag? *
2 points
Step 1: 350=2(150)+50 Step 2: 150=3(50)+0 Step 3: Greatest amount: 50 kg
Step 1: 350=2(150)+50 Step 2: 150=2(50)+0 Step 3: Greatest amount: 50 kg
Step 1: 350=2(150)+50 Step 2: 150=3(50)+0 Step 3: Greatest amount: 150 kg
Step 1: 350=2(150)+50 Step 2: 150=2(50)+0 Step 3: Greatest amount: 150 kg

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

A worker needs to pack 350 kg of rice and 150 kg of wheat in bags such that each bag weighs the same. Each bag should either contain rice or wheat. Which option shows the correct steps to find the greatest amount of rice/wheat the worker can pack in each bag

Option : I

Step 1 : 350=2(150)+50

Step 2 : 150=3(50)+0

Step 3 : Greatest amount: 50 kg

Option : II

Step 1: 350=2(150)+50

Step 2: 150=2(50)+0

Step 3: Greatest amount: 50 kg

Option : III

Step 1: 350=2(150)+50

Step 2: 150=3(50)+0

Step 3: Greatest amount: 150 kg

Option : IV

Step 1: 350=2(150)+50

Step 2: 150=2(50)+0

Step 3: Greatest amount: 150 kg

EVALUATION

Here it is given that

A worker needs to pack 350 kg of rice and 150 kg of wheat in bags such that each bag weighs the same.

Each bag should either contain rice or wheat

Here the given weights are 350 kg and 150 kg

Now 350 > 150

We now find HCF step by step by using Euclid's division algorithm.

Step : 1

$\sf{350 = 2 \times 150 + 50}$

Step : 2

$\sf{150 = 3 \times 50 + 0}$

Step : 3

So HCF = 50

Greatest amount = 50 kg

FINAL ANSWER

Hence the correct option is

Option : I

Step 1 : 350=2(150)+50

Step 2 : 150=3(50)+0

Step 3 : Greatest amount: 50 kg

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