Math, asked by aninditagiri00, 1 month ago

limit as X approaches 1
of x^2-3x+2/x^2-4x+3​

Answers

Answered by Anonymous
0

Answer:

1/2

Step-by-step explanation:

x^2-3x+2=(x-2)(x-1)

x^2-4x+3=(x-3)(x-1)

cancel (x-1) from numerator and denominator

then put the value of x

x-2/x-3=1-2/1-3= -1/-2=1/2

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