Math, asked by raviathira758, 1 month ago

'A' working alone take 80 days more than time taken by A and B working together to complete the work,B working alone takes 20 days more than the time taken by A and B working together to complete the work,find the time taken by A to complete the job working?​

Answers

Answered by kavitajha450
0

Answer:

The answer is:-

Step-by-step explanation:

Let A take x

B take y has together is hours =(

x

1

+

y

1

) in of work

Let time be t

t(

x

1

+

y

1

)+8=

x

t+8

y

t

=

x

8

t(

x

1

+

y

1

)=

y

t+4.5

x

t

=

y

4.5

y

x

=

t

8

;

y

x

=

4.5

t

t

8

=

4.5

t

⇒t

2

=36

t=6hours.

Therefore, the answer is 6hrs.

Mark my answer as the BRAINLIEST ⭐⭐

Answered by akritirajput07
2

Answer:

Step-by-step explanation:

A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 41/2 hours more to complete the job than they both working together.

another answer

Let A and B together take x hours to complete the work.

Then, A alone takes (x + 8) hours

And

B alone takes (x+92)

  hours to complete the work

Then,

⇒1(x+8)+1(x+92)=1x⇒1(x+8)+2(2x+9)=1x⇒x(4x+25)=(x+8)(2x+9)⇒2x2=72⇒x2=36⇒x=6

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