Question

A works at a speed 2times than B so that b takes 50 days more than a to complete a piece of work. Find the number of days required by both a and b to complete the Work​

Answer 1

A works at a speed 2 times the speed B.

efficiency ratio of A : B = 2:1

A took x days to complete a work

B took (x + 50) days to complete a work

Total work = no. of days * efficiency

$2 \times x = 1 \times( x + 50)$

$x = 50$

A complete a work in 50 days

B complete a work in 100 days

if A works at a speed 2 times more than B.

efficiency ratio of A : B = 3:1

A took x days to complete a work

B took (x + 50) days to complete a work

Total work = no. of days * efficiency

$3\times x = 1 \times( x + 50)$

$x = 25$

A complete a work in 25 days

B complete a work in 75 days

(I'm little bit confused with the question. efficiency more than or 2 times the speed. so I add both cases)