Math, asked by sonai25, 11 months ago

A works twice as fast as B. If both of them can together finish a piece of work in 12 days,then B alone can do it in how many days? ​

Answers

Answered by yadavpiyush93339
0

Answer:

12 days

Step-by-step explanation:

Let completes in x days.

B completes twice as A then B works in 2x

1/A+1/B=1/8

1/X+1/2X=1/8

Taking LCM

2/2X+1/2X=1/8

3/2X=1/8

2X/3=8

2X=24

X=12

So,B can do work in 12+12=24 days

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