A works twice as fast as B. If both of them can together finish a piece of work in 12 days,then B alone can do it in how many days?
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Answer:
12 days
Step-by-step explanation:
Let completes in x days.
B completes twice as A then B works in 2x
1/A+1/B=1/8
1/X+1/2X=1/8
Taking LCM
2/2X+1/2X=1/8
3/2X=1/8
2X/3=8
2X=24
X=12
So,B can do work in 12+12=24 days
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