Question

A works twice as fast as B. If both of them can together finish a piece of work in 12 hours. How much time will B take to finish the work alone?​

Answer 1

Answer:

18 Hours

Step-by-step explanation:

Let time taken by B to do the work = 2t

Time taken by A = t

1 day work of A and B = 1/2t + 1/t

= 1+2/2t

= 3/2t ( Equation No. 1 )

So 1 hour work of A and B = 1/12 (Equation Number 2 )

1/12=3/2t ( Do Cross Multiplication )

= 36=2t

= t = 36/2 ( Divide )

= 18 hours

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