Question

A. (x+1)(x-2) =
a) 3(x-2) 3(x+1) b) 3(x+2) 3(x+1)​

Answer 1

Step-by-step explanation:

$we \: will \: solve \: this \: by \: the \: formula \: that \: \\ (x + a)(x + b) = {x}^{2} + (a + b)x + ab\: \\</p><p>A. (x+1)(x-2)={x}^{2} + (1 - 2)x + ( - 2 \times 1) \\ = {x}^{2} - x - 3 \\ \\ a) \: \: 3(x - 2) \times 3(x + 1) \\ = 3((x - 2)(x + 1)) \\ = 3( {x}^{2} - x - 3) \\ = 3 {x}^{2} - 3x - 9 \\ \\ b) \: \: 3(x + 2) \times 3(x + 1) \\ = 3((x + 2)(x + 1)) \\ = 3( {x}^{2} + (1 + 2)x + 1 \times 2) \\ = 3( {x}^{2} + 3x + 2) \\ = 3 {x}^{2} + 9x + 6 \\ \\ <strong>pls \: mark \: as \: the \: brainliest</strong>$