Math, asked by rajibborthakur763, 11 months ago

√a+x-√a-x÷√a+x+√a-x please give the answer

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Answered by Anonymous
17

Answer:

Hey mate!

Here's your answer to a similar query!

If x=(√(a+2b)+√(a-2b))/(√(a+2b)-√(a-2b)) … then prove that bx2-ax+b=0

x =(√(a+2b)+√(a-2b))/(√(a+2b)-√(a-2b))

use Component and dividend

(x+1)/(x-1) = √(a+2b)/√(a-2b)

square both sides

(x² + 2 x + 1)/(x^2-2x + 1) = (a+2b)/(a-2b)

again use component and dividend

(x² + 1)/(2x) = (a)/(2b)

or bx^2 +b = ax

or bx^2 - ax + b = 0

Answered by Anonymous
3

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