Question

a^x=b^y=c^Z. prove that abc=1​

Answer 1

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sorryyyyyyyyyyy

i hate mathsssss

so i dont have the answer

Answer 2

${a}^{x} = {b}^{y} = {c}^{z}$

Here,

${a}^{x} = {b}^{y} \\ a = \sqrt[x]{( {b}^{y} )} \\ a = {b}^{ \frac{y}{x} }$

${b}^{y} = {c}^{z} \\ b = {c}^{ \frac{z}{y} }$

${c}^{z} = {a}^{x} \\ c = {a}^{ \frac{x}{z} }$

Now,

$abc = > {b}^{ \frac{y}{x} } \times {c}^{ \frac{z}{y} } \times {a} ^{ \frac{x}{z} } \\ \\ \: \: \: \: \: = > {(bca)}^{0} = 1$

Hence, Proved that ABC = 1