a^x +b^y=c^z
then find a, b, c
and x, y, z
Answers
Step-by-step explanation:
ax=b → (i)
by=c → (ii)
cz=a → (iii)
Using (i) and (ii), we can write
axy=c → (iv)
Using (iii) and (iv), we get
axyz=a1 [Since, a1=a]
or, xyz=1 [Since the bases are equal, the powers will be equal as well]
.
Hope it helps! :)
or
a can be written as ——a=10^log a
Similarly ——————- b= 10^log b
——————————— c= 10^log c
Where a,b,c are positive
(We know log of 10=1, log of 100=2, log of 1000=3
10 can be written as 10=(10 )^(log 10)
100 can be written as 100=( 10)^(log 100)
1000=(10)^(log 1000)
=10^3=1000 )
a^x=b
Now (10)^(log a )^x=10^log b
Since base is same (10),we can equate the exponents.
(log a)^x = log b
Or x log a =log b
Or x = (log b ) / (log a)
Similarly y=(log c)/(log b)
z =(log a) /( log c)
xyz =(log b)/(log a) X (log c)/(log b) X (log a)/( log c) = 1
xyz = 1 ANSWER.
Answer:
infinite answers
Step-by-step explanation:
there are infinite values of a, b, c and x, y, z
example
if a=b=c=1
and x=y=1 ; z=2
satisfied the equation
hope u may understand
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