Question

A={x;is a factor of x²-5x+6},B={x:x is a factor of x²-4x+3} find A-B,B-A,

Answer 1

i ) x²-5x+6

= x²-2x-3x+6

= x(x-2)-3(x-2)

= (x-2)(x-3) -------( 1 )

ii ) x²-4x+3

= x²-1x-3x+3

= x(x-1)-3(x-1)

= (x-1)(x-3) ------( 2 )

Now ,

A={x;is a factor of x²-5x+6}

A = {(x-2),(x-3)}

B={x:x is a factor of x²-4x+3}

B = { (x-1),(x-3)}

A-B={(x-2),(x-3)}-{(x-1),(x-3)}

= {(x-2)}

B-A= {(x-1),(x-3)}-{(x-2),(x-3)}

= {(x-1)}

A-B ≠ B-A

••••