A = { x : x is a natural number } B = {x : x an even natural number}
C = {x : x an odd natural number } D = {x : x is a prime} then find
i) A - B ii) B ∩ D iii) A – C iv) B ∪ C
Answers
Step-by-step explanation:
Given :-
A = { x : x is a natural number }
B = {x : x an even natural number}
C = {x : x an odd natural number }
D = {x : x is a prime}
To find :-
Find the following
i) A - B
ii) B ∩ D
iii) A – C
iv) B ∪ C
Solution :-
Given that :-
A = { x : x is a natural number }
A = { 1,2,3,4,...} ----------(1)
B = {x : x an even natural number}
B = { 2,4,6,8,...} ----------(2)
C = {x : x an odd natural number }
C = { 1,3,5,7,...} -----------.(3)
D = {x : x is a prime}
D = { 2,3,5,7...} -----------(4)
Now,
i) A - B :-
A- B
= { 1,2,3,4,...} - { 2,4,6,8,...}
A- B = { 1,3,5,7...}
ii)B ∩ D :-
B ∩ D = { 2,4,6,8,...} ∩ { 2,3,5,7...}
B ∩ D = { 2}
iii) A – C :
A – C = { 1,2,3,4,...} - { 1,3,5,7,...}
A – C = { 2,4,6,8,... }
iv)B ∪ C:-
B ∪ C = { 2,4,6,8,...} ∪ { 1,3,5,7,...}
B ∪ C = {1,2,3,4,5,6,7,8,...}
Answer:-
i)A- B = { 1,3,5,7...} = C
ii)B ∩ D = { 2}
iii)A – C = { 2,4,6,8,... } = B
iv)B ∪ C = {1,2,3,4,5,6,7,8,...} = A
Used formulae:-
If A and B are two sets then
- A ∪ B is the set of elements in either A or in B or in both.
- A ∩ B is the set of common elements in both A and B.
- A – B is the set of elements in only A i.e.The elements belongs to A and doen not belongs to B.
- B – Ais the set of elements in only B i.e.The elements belongs to B and doen not belongs to A.