verify wheather x=-1/✓3 and 2/✓3 are zeroes of p(x)=3x²-1 or not
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Step-by-step explanation:
if x =1√3, then 3x²-1 =0
3*(1√3)^2-1
=3*3-1
=9-1
=8
so 3x²-1 is not equal to 0. So 1√3 is not a zero.
similarly
if x =2√3, then
3*(2√3)^2-1
=3*12 -1
=36-1
=35.
so 2√3 is not a zero.
please mark as brainlieast
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