A=(x:x is a prime factor of 7854) B=(x:x is a prime factor of 2090) prove that AuB-AnB=(A-B)u(B-A)
Answers
Answered by
12
Here,
A = {x:x is a prime factor of 7854}
=> A = {2, 3, 7, 11, 17}
And,
B = {x:x is a prime factor of 2090}
=> B = {2, 5, 11, 19}
Now,
AuB = {2, 3, 5, 7, 11, 17, 19}
AnB = {2, 11}
=> AuB-AnB = {3, 5, 7, 17, 19} --- (1)
And,
A-B = {3, 7, 17}
B-A = {5, 19}
=> (A-B)u(B-A) = {3, 5, 7, 17, 19} --- (2)
From 1 and 2, we get
AuB-AnB = (A-B)u(B-A)
Hence proved
Answered by
2
Answer:
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Step-by-step explanation:
Here,
A = {x:x is a prime factor of 7854}
=> A = {2, 3, 7, 11, 17}
And,
B = {x:x is a prime factor of 2090}
=> B = {2, 5, 11, 19}
Now,
AuB = {2, 3, 5, 7, 11, 17, 19}
AnB = {2, 11}
=> AuB-AnB = {3, 5, 7, 17, 19} --- (1)
And,
A-B = {3, 7, 17}
B-A = {5, 19}
=> (A-B)u(B-A) = {3, 5, 7, 17, 19} --- (2)
From 1 and 2, we get
AuB-AnB = (A-B)u(B-A)
Hence proved
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