A = {x:xen, x is a factor of 12}
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Factors of 12 are 1,2,3,4,6,12. So, the prime factors of 12 are 2,3.
We write the set A in roster form as A={2,3} and hence n(A)=2.
(ii) B={x:x∈W,x≤5}. In Tabular form, B={0,1,2,3,4,5}.
The set B has six elements and hence n(B)=6
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