Question

a(x+y) + b(x - y) – ( a^2 – ab +b^2) = 0
a(x+y) – b(x - y) – ( a^2 + ab +b^2) = 0
$ans = x = \frac{b {}^{2} }{2a} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = a + ( \frac{b {}^{2} }{2a} )$
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Answer 1

Answer:

$a(x + y) + b(x - y) - ( {a}^{2} - ab + {b}^{2} ) = 0 \\ ax + ay + bx - by - {a}^{2} + ab - {b}^{2} = 0 \\ ax + bx + ay - by + ab - {a}^{2} - {b}^{2} = 0 \\ x(a + b) + y(a - b) + ab - {a}^{2} - {b}^{2} = 0 \\ (x + y)(a + b) + ab - {a}^{2} - {b}^{2} = 0 \\ (x + y)(a + b) + ab - (a - b)(a + b) = 0$

hope it helps

Answer 2

Step-by-step explanation:

HOPE IT HELPS YOU........