Question

(a^x-y)^x+y.(a^y-z)^y+z.(a^z-x)^z+x

Answer 1

On multiplying the powers as (a+b) (a-b)
We get the powers as a2 - b2
So,
a^x2-y2* a^y2 - z2* a^z2-x2
Same base so, adding powers
${a}^{ {x}^{2} - {y}^{2} + {y}^{2} - {z}^{2} + {z}^{2} - {x}^{2} }$
Which comes,
${a}^{0} = 1$