Question

a(x+y+z)+b(x+y+z)+c(x+y+z)​

Answer 1

Answer:

Step-by-step explanation:

a(y+z)=b(z+x)=c(x+y)  

Assume n= a(y+z)=b(z+x)=c(x+y)  

n=a(y+z) ,n= b(z+x) , n= c(x+y)  

y+z = (n/a).....................(1)  

z+x = (n/b).....................(2)  

x+y = (n/c).....................(3)  

subtracting (2) - (1) , (3) - (2) , (1) - (3) we get  

x - y = n( a - b )/ab ..................(4)  

y - z = n ( b - c )/bc...................(5)  

z - x = n( c - a )/ac...................(6)  

x-y/c(a-b) = [ n ( a - b )/ab ] / c( a - b )  

= n/abc  

y-z/a(b-c) = [ n ( b - c )/bc ] / a( b - c )  

= n/abc  

z-x/b(c-a) = [ n ( c - a )/ac ] / b( c - a )  

= n/abc  

y-z/a(b-c)=z-x/b(c-a)=x-y/c(a-b

Answer 2

Answer:

a(x+y+z)+b(x+y+z)+c(x+y+z)

=(x+y+z)(a+b+c)

This is the concept based on identities...

I hope this helps...

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