a=x1/3y1/3+x-1/3y-1/3 find the value of a3-3ay-x
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Question:
a=x^1/3.y^1/3+x^(-1/3).y^(-1/3) find a^3-3ay-x=
Solution is in the attachment
Here in this question we have to assume the value of X & y.
I have assume x= 8 & y= 1
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Solution is = a³-3ay-x=
0.125= 125/1000= 1/8
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Hope this will help you.....
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Simply take x = 27and y = 1 you will get A=10/3 Now a³-3ay-x = 1000/27-10-27=1/27 Put the value in optionsY²/x = 1/27
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