Math, asked by vikramsingh0786, 1 year ago

a=x1/3y1/3+x-1/3y-1/3 find the value of a3-3ay-x

Answers

Answered by nikitasingh79
1
Question:

a=x^1/3.y^1/3+x^(-1/3).y^(-1/3) find a^3-3ay-x=

Solution is in the attachment

Here in this question we have to assume the value of X & y.

I have assume x= 8 & y= 1
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Solution is = a³-3ay-x=
0.125= 125/1000= 1/8
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Hope this will help you.....
Attachments:
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