A year ago a father, whose present age is 'x' years was 4 times as old as his son whose present age is 'y' years.
Anonymous:
more details are required about question. it is incomplete
no we have to make a formulae
okh
ok
what is the relation between father's and son's present ages?
i.e how are x & y related to each other
Present:Father's age=x
Present son age=y past son's age=y-4 past father's age =x-4. Therefore 4(y-4)=(x-4) or 4y-x=12
no sorry i was wrong above
Answers
Answered by
2
equation is
x-1 = 4 (y-1)
or x-1 = 4y-4
or x-4y = -3
or x-4y+3 = 0
x-1 = 4 (y-1)
or x-1 = 4y-4
or x-4y = -3
or x-4y+3 = 0
correct Sk456
Answered by
0
Hi !
Let the present ages of father and son be "x" and "y" respectively.
Their ages , one year before , would be "x - 1" and "y - 1"
According to the question ,
4( y - 1 ) = x - 1
4y - 4 = x - 1
x - 1 + 4 - 4y = 0
x + 3 - 4y = 0
Let the present ages of father and son be "x" and "y" respectively.
Their ages , one year before , would be "x - 1" and "y - 1"
According to the question ,
4( y - 1 ) = x - 1
4y - 4 = x - 1
x - 1 + 4 - 4y = 0
x + 3 - 4y = 0
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