Chemistry, asked by SakshamSambyal, 1 year ago

A yellowish coloured compound 'X' is a photosensitive material. On exposure to sunlight, it gives a greyish substance 'Y' and brown fumes of a gas 'Z' . Identify X, Y and Z . How will you obtain 'X' from the nitrate salt of 'Y' ??? PLEASE ANSWER CORRECTLY. NO SPAM PLS​ Only for Expert​

Answers

Answered by Abhishek474241
3

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SEE THE GIVEN ATTACHMENT

(2) SILVER BROMIDE CAN BE OBTAINED FRM SALT OF SILVER

AgNo3+KBr---->>>AgBr+KNo3

IT IS A DISPLACEMENT REACTION

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Answered by Anonymous
2

⚡Here is your answer⚡

1) Silver bromide on exposing to sun light,decomposes to silver metal and bromine gas.

Silver bromide--is a salt sensitive to sun light.

Bromine gas-- Brown colour gas.

Silver--is greyish colour metal

AgBr (s)---->Ag (s)+ Br2 (g)

So, X--AgBr

Y--Ag

Z--Bromine gas

Silver bromide can be obtained from the salt of silver that is silver nitrate can be used.

AgNO3 + KBr -->AgBr + KNO3

This is a displacement reaction where potassium displaces silver from AgNO3 and form AgBr.

⭐Mahir⭐

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