TanA+SecA-1÷TanA-SecA+1=1+sinA÷CosA
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hey mate ! here is your answer
Step-by-step explanation:
by L.H.S
tanA + secA - 1/ tanA - secA + 1
☆ tenA + secA - sec^2A - tan^2A / tanA - secA (becouse, tan^2A - sec^2A = 1)
☆ (tanA+ secA) + (tanA + secA)(tanA - secA) / tanA -secA + 1
☆ (tanA + secA) (1 + tanA - secA) / 1 + tanA - secA
☆ tanA + secA
☆ sinA/cosA + 1/cosA
☆ 1 + sinA/cosA = T.H.S
hope this help you☺
Answered by
1
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your answer attached in the photo
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