Question

a yellowish coloured compound 'X' is photosensitive material. On exposure to sunlight OT gives a greyish substance 'y'and from fumes of gas 'z' identify X, Y and Z. How will you obtain X form the nitrate salt of Y?

Answer 1

I)Silver bromide on exposing to sunlight, decomposes to silver metal and bromine gas.
Silver bromide--Is a salt sensitive to sunlight.
Bromine gas --Brown colour gas.
Silver - Is greyish colour metal
AgBr(s)----> Ag(s) + Br2 (g)
So, X- AgBr
Y--Ag
Z- Bromine gas

II) Silver bromide can be obtained from the salt of silver that is silver nitrate can be used.
AgNO3 +KBr ----->AgBr + KNO3
This is a displacement reaction where potassium displaces silver from AgNO3 and forms AgBr

Answer 2

Compound 'X' is " Silver Bromide ".

Silver Bromide is photosensitive.

On exposure to sunlight , it gives a grayish substance "Silver " and fumes of gas " Bromine ".

Hence,

X ---- SILVER BROMIDE

Y ---- SILVER

Z ---- BROMINE

Reaction is =>>

2AgBr --------------> 2Ag + Br2

(Sunlight )

____________________________

☆ Silver Bromide can be obtained from the salt of silver ( Silver Nitrate ) by reacting with potassium bromide.

Reaction is =>>

Ag(NO)3 + KBr -------> AgBr + KNO3

Thanks

@mannat