A zero order reaction is 20% complete in 20 minutes. calculate the value of the rate constant. in what time will the reaction be 80% complete?
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Answer:
144.25 min
Explanation:
K= 1/t ln (a/a-x)
K = rate constant
t =time
a = initial lconcentration of the reactant
x = amount of reactant reacted in time t
x =20/100 x a ⇒x=0.2a
a - x =0.8a
k = 1/20 ln (a /0.8x)
t= ?
x =0.8a
a - x =0.2a
K = 1/t ln (x/0.2x)
1/20 (10/8) = 1/t ln (10/2)
t = 20 x InS / In (S/4)
= 144.25 mins
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