Question

A zero order reaction is 20% complete in 20 minutes. calculate the value of the rate constant. in what time will the reaction be 80% complete?

Answer 1

Answer:

144.25 min

Explanation:

K= 1/t ln (a/a-x)

K = rate constant

t =time

a = initial lconcentration of the reactant

x = amount  of reactant reacted in time t

x =20/100 x a ⇒x=0.2a

a - x =0.8a

k = 1/20 ln   (a /0.8x)

t= ?

x =0.8a

a - x =0.2a

K = 1/t ln (x/0.2x)

1/20 (10/8) = 1/t ln (10/2)

t = 20 x InS / In (S/4)

= 144.25 mins

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