A10g bullet is shot from a 5kg gun with a velocity of 2500 m/s.what is the the speed of recoil of the gun.
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according to law of Conservation of momentum m1 v1= m2v2
0.01kg *v2=5kg *2500m/s²
v2= 5 * 2500/0.01
v2= 1250000m/s²
=1250 km/s²
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