Question

a2-12a+35 factorize​

Answer 1

QUESTION:

a2-12a+35 factorize.

ANSWER:

GIVEN quadratic equation is in the form of

$a {x}^{2} + bx + c$

STEP 1:

Split the middle term in such a way that it's sum equal to b i.e. . -12 and product equal to a × c.

${a}^{2} - 7a - 5a + 35$

STEP 2

TAKING common factor

$a(a - 7) - 5(a - 7)$

$(a - 5)(a - 7) \: are \: the \: factors.$

now :

$a - 5 = 0 \\ a = 5$

$a - 7 = 0 \\ a = 7$

FINAL ANSWER :

$\huge\red{a= 5 \: and \: 7}$

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Answer 2

SOLUTION:-

Given that a²-12a+35.

To factorise it.

So, a²-12a+35

factorization by splitting method.

a² - 7a - 5a + 35

=> a( a - 7 ) -5 ( a - 7 )

=> (a - 5 ) ( a - 7 )

Therefore, (a-5) and (a-7) are the factors of a²-12a+35.

THANKS.